Solution: A four-digit number ranges from 1000 to 9999. A number is divisible by 5 if its last digit is 0 or 5. The smallest four-digit number divisible by 5 is 1000, and the largest is 9995. These form an arithmetic sequence with first term 1000, common difference 5, and last term 9995. The number of terms is given by \(\frac{9995 - 1000}{5} + 1 = \frac{8995}{5} + 1 = 1799 + 1 = 1800\). Therefore, there are \(\boxed{1800}\) four-digit numbers divisible by 5.

Tue, 05 May 2026 08:18:42 +0000

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