An arithmetic sequence has a first term of 7 and a common difference of 5. The nth term is equal to the sum of the first n positive integers. Find n. - Redraw

Understanding the Context

The Silent Math Behind Everyday Patterns

What’s striking is how this sequence mirrors real-world phenomena: the steady rise of income, consistent progress in goals, or the predictable growth seen in investment returns. When the first term is 7 and each step increases by 5, the sequence unfolds as 7, 12, 17, 22, 27… Meanwhile, the sum of the first n positive integers follows the formula n(n + 1)/2—a cornerstone of arithmetic series.

Understanding when these two expressions align—the nth term equals the sum—sheds light on how numerical relationships unlock deeper analytical thinking, a skill increasingly vital in a data-driven society.

Key Insights

Why This Pattern Is Trending Now

In recent months, interest in mathematical structures has surged across creator-led education, financial literacy posts, and puzzle-based learning platforms. This problem taps into a growing curiosity about how everyday life answers mathematical truths—echoing trends where simplicity in form hides powerful applications.

Beautifully, it connects abstract arithmetic to tangible outcomes. Whether guiding budget planners or developing algorithmic logic, such patterns reinforce logic as a universal tool for problem-solving and informed decision-making.

How the Sequence Equals the Sum: A Clear Explanation

Final Thoughts

The nth term of an arithmetic sequence is given by:
aₙ = first term + (n – 1) × common difference
Here, 7 + (n – 1) × 5 = n(n + 1) / 2

Let’s simplify the left side:
7 + 5n – 5 = 5n + 2

Set it equal to the sum formula:
5n + 2 = n(n + 1) / 2

Multiply both sides by 2 to eliminate the denominator:
10n + 4 = n² + n

Bring all terms to one side:
n² + n – 10n – 4 = 0
n² – 9n – 4 = 0

Now solve this quadratic using the quadratic formula:
n = [9 ± √(81 + 16)] / 2 = [9 ± √97] / 2