A rectangle has a length that is 3 times its width. If the perimeter of the rectangle is 48 meters, what is the area of the rectangle?

Mon, 04 May 2026 07:48:48 +0000

**1. Intro: Curiosity Meets Calculated Precision**
In a world increasingly shaped by data, geometry puzzles prove more than quizzes—they spark mental clarity and practical problem-solving skills. One recurring question gaining quiet traction across the US is: *A rectangle has a length that is 3 times its width. If the perimeter is 48 meters, what is the area?* This isn’t just math for math’s sake. It reflects how everyday spatial reasoning intersects with real-world applications—from architecture to interior design. Understanding this relationship unlocks clearer thinking about proportions, space efficiency, and structural design. Let’s break it down with clarity, precision, and relevance to everyday curiosity. **2. Why This Rectangle Piques Attention in Modern America**
Rectangles dominate American infrastructure and design—room layouts, digital screens, building plans. The ratio of 3:1 isn’t random: it balances functionality and efficiency, echoing principles in user-centered design. As homeowners, builders, and digital creators seek optimized space—whether in apartments, workspaces, or product packaging—this configuration surfaces in searches and conversations. It mirrors trends in data-driven decision-making, where precise dimensions inform cost, material use, and aesthetics. The question reflects growing public interest in geometry’s role beyond classrooms, where simple equations solve real-life planning challenges. **3. How It Actually Works: Solving the Rectangle Puzzle**
Given: length = 3 × width
Perimeter = 48 meters Perimeter formula:
\( P = 2(L + W) \)
Substitute \( L = 3W \):
\( 48 = 2(3W + W) = 2(4W) = 8W \)
So, \( W = 48 ÷ 8 = 6 \) meters