demons obsession - Redraw

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📰 So indeed, \( (z^2 + 2)^2 = 0 \), so roots are \( z = \pm i\sqrt{2} \), each with multiplicity 2. But the **set of distinct roots** is still two: \( i\sqrt{2}, -i\sqrt{2} \), each included twice. But the problem asks for **the sum of the real parts of all complex numbers \( z \)** satisfying the equation. Since real part is 0 for each, even with multiplicity, the sum is still \( 0 + 0 = 0 \). 📰 Alternatively, interpret as sum over all **solutions** (with multiplicity or not)? But in algebraic contexts like this, unless specified, we consider distinct roots or with multiplicity. But multiplicity doesn't affect real part — each root contributes its real part once in evaluation, but the real part function is defined per root. However, in such symmetric cases, we sum over distinct roots unless told otherwise. 📰 But here, the equation \( (z^2 + 2)^2 = 0 \) has roots: 📰 Thumbnail Ready You Wont Believe How Tygo Stock Is Changing The Market 2619429 📰 You Wont Believe What Happened After Joining Bbo Comstop What Youre Doing Now 1947604 📰 Ps Plus Cost 4364999 📰 Royal Inn Motel 8385862 📰 Shocking Discovery Radioactive Spider Infests Abandoned City You Wont Believe What Was Found 3047210 📰 Gray Paint 1004560 📰 Standard Shower Curtain Size You Cant Live Withoutlarge Enough For Every Shower 8270232 📰 Download Transit App 5322211 📰 Top Rated Changing Table Topper Secretly Saves You Hours Dont Miss Out 8549918 📰 The Rifleman Survived The Last Battle No One Believes 6462419 📰 Superbox Tv 6485187 📰 You Wont Believe What This Pit Achieves When Its Properly Ventilated 7009324 📰 Windows 11 Compatibility Checker The Fast Way To Spot Problematic Apps Before Its Too Late 3156913 📰 Unique The Jade Mk Thats Booming On Social Media Dont Miss Out 3963783 📰 Your Brooms Whispering Secretswhat Happens When It Pushes More Than Dust 7920269