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Understanding the Context
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510825 2020-06-30
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📰 Thus, $ D = (4, 5, 6) $. However, this coincides with point $ B $, which implies $ ABCD $ collapses into a degenerate parallelogram (a line segment), not a valid 3D parallelogram.
📰 Thus, the only point $ D $ satisfying parallelogram vector conditions is $ (4,5,6) $, but it lies on the line through $ A, B, C $, so $ ABCD $ is degenerate.
📰 But the problem allows integer coordinates and does not specify non-degeneracy, so technically:
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