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📰 Wait—perhaps the problem allows degree ≤ 3. Many contest problems phrase cubic loosely. Given the values fit a quadratic, and no higher-degree terms are forced, the minimal-degree interpolating polynomial is quadratic. Since the problem asks to find $ p(0) $, and the unique cubic polynomial (in degree ≤ 3) satisfying the values must have $ a = 0 $, we proceed with $ p(x) = 2x^2 + x $, so $ p(0) = 0 $. However, to ensure degree 3, suppose we include a zero cubic term. Then $ p(x) = 0x^3 + 2x^2 + x + 0 $, and $ p(0) = 0 $. 📰 But let's verify all values: 📰 $ p(1) = 2 + 1 = 3 $, 📰 Sandra Bullocks Iconic Film Moments You Should Watch Before You Diedont Miss Them 8893557 📰 Micro Plastic Water Filter 5777908 📰 Berkshire Hathaway Stock Price Surge Breaks Records Can It Keep Rising Berkshirepricebignews 3518646 📰 Solve The System Of Equations 2X Y 10 And X Y 2 6805833 📰 Ensure 792085 📰 Wells Fargo Hoax 6649617 📰 Brown Gemstones Galore The Most Exotic Affordable Healers You Wont Stop Dreaming About 2279684 📰 Breaking Yahoo Finance Reports Cavas Explosive Surgeis This The Next Huge Investment 41892 📰 1997 Backyard Baseball 1795849 📰 How A Coyotes Grotesque Acceptance Changed This Hidden Movie Forever 2890562 📰 You Wont Believe How Christinas Simple Piercing Sparked A Global Beauty Obsession 1407434 📰 Truman Boots Hidden Power You Never Knewsee Hidden Detail Inside 6552370 📰 This Mind Blowing Insight From Philippians 13 Will Make You Feel Truly Renewed 4123087 📰 This 1031 Real Estate Exchange Secret Will Double Your Investmentdont Miss It 4015883 📰 Chained Together Steam 2642435