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Home » Konklusion: $ 5 \mid 0 $? wahr - Redraw

Konklusion: $ 5 \mid 0 $? wahr - Redraw

📅 May 4, 2026 👤 scraface

May 04, 2026

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\frac{\pi r^2}{A} = \frac{\pi r^2}{r \cdot s} = \frac{\pi r}{s}
Since \( s = \frac{a + b + z}{2} \) and \( a + b = z + 2r \), we have:
s = \frac{z + 2r + z}{2} = z + r
\frac{\pi r}{z + r}
\boxed{\frac{\pi r}{z + r}}
An equilateral triangle has an area of \( 36\sqrt{3} \) square centime...
The area \( A \) of an equilateral triangle with side length \( s \) i...
Given \( A = 36\sqrt{3} \), we solve for \( s \):
\frac{\sqrt{3}}{4} s^2 = 36\sqrt{3}
s^2 = 144 \quad \Rightarrow \quad s = 12

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