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📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 To solve this problem, we need to find the number of ways to choose exactly 3 aces and 2 non-ace cards from a standard deck of 52 cards.

📌 The number of ways to choose 3 aces from 4 is:

📌 Choosing 2 non-ace cards from the remaining 48:

📌 The number of ways to choose 2 cards from 48 non-aces is:

📌 A team of 5 members is to be formed from a group of 10 candidates. How many different teams can be formed if 2 specific candidates must always be included?

📌 Since 2 specific candidates must always be included, we only need to choose the remaining 3 members from the other 8 candidates.

📌 Choosing 3 members from the remaining 8 candidates:

📌 The number of ways to choose 3 members from 8 is:

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