At least one is divisible by 2, and at least one by 4 (since there are five numbers), ensuring divisibility by \( 2^3 = 8 \). However, the product is already guaranteed by \( 2 \times 3 = 6 \), and typically one is divisible by 4 but not consistently ensuring a higher power.

Wed, 06 May 2026 15:38:44 +0000

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