Solution: The total number of possible state combinations is $2^5 = 32$. The number of ways to choose 2 elements to be active is $\binom{5}{2} = 10$. Since each combination is equally likely, the probability is $\frac{10}{32} = \frac{5}{16}$. Thus, the final answer is $\boxed{\dfrac{5}{16}}$.

Wed, 06 May 2026 23:26:12 +0000

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