A science communicator is creating an educational video about projectile motion. Suppose a projectile is launched from the ground with an initial velocity $v_0$ at an angle $\theta$ to the horizontal. Given the equation of the trajectory $y = x\tan\theta - \frac{g}{2v_0^2\cos^2\theta}x^2$, find the horizontal distance $x$ at which the projectile reaches its maximum height.

Tue, 05 May 2026 15:17:46 +0000

Content under review