A rectangles length is three times its width. If the perimeter of the rectangle is 64 meters, what is the area of the rectangle?

Wed, 06 May 2026 22:01:11 +0000

**Discover the math behind a classic rectangle puzzle—why length and width matter, and how to unlock its area soaring to 192 square meters** Why are so many people turning to simple geometry like this? In today’s fast-moving digital landscape, even basic rectangle problems reflect real-world applications—from architecture and interior design to budgeting for construction or space planning. Understanding how to calculate area from perimeter isn’t just academic—it’s a foundation for smart decision-making, both personal and professional. A rectangles length is three times its width. If the perimeter of the rectangle is exactly 64 meters, what is the area? This question isn’t just a classroom exercise; it surfaces naturally in trends focused on spatial efficiency, digital design tools, and content-driven ROI planning. Users confidently search for these answers to visualize space, optimize layouts, or understand material needs—without ever touching adult content. To solve this, start with the perimeter formula: P = 2(length + width). Given that the length (L) equals three times the width (W), write L = 3W. Substituting into the perimeter equation: 64 = 2(3W + W) = 2(4W) = 8W. Solving gives W = 8 meters. Then L = 3 × 8 = 24 meters.