We verify by noting that the number of ways to partition a set of 5 labeled elements into indistinct, possibly empty subsets (with exactly 4 unlabeled bins) is equivalent to the number of integer partitions of 5 into at most 4 parts, which confirms 6. - Redraw

Understanding the Context

What Does It Mean to Partition a Set into Indistinct Subsets?

Consider a set with 5 distinct elements, such as {A, B, C, D, E}. A partition divides this set into disjoint, non-overlaping subsets whose union is the entire set. When the bins (or subsets) are indistinct, the order of the subsets does not matter. Furthermore, if empty subsets are allowed, the partition can contain up to 4 subsets—since we require exactly 4 bins, but some may be empty.

However, exactly 4 non-empty unlabeled bins is impossible if we start with only 5 elements: to form 4 non-empty subsets, each bin must contain at least one element, totaling 4 elements. That leaves one element unassigned—invalid under the “exactly 4 bins” constraint unless empty bins are counted. But the problem clarifies: we seek partitions into exactly 4 indistinct subsets including empty bins, meaning the total number of non-empty bins is ≤ 4. Still, standard interpretation focuses on at most 4 non-empty subsets forming 4 bins total when empty bins are allowed.

But more precisely, the key idea is: the number of ways to partition 5 labeled items into exactly 4 (not necessarily non-empty) indistinct subsets corresponds uniquely to the integer partitions of 5 into at most 4 parts. Each part size corresponds to the number of elements in a bin, and since bins are indistinct, only the multiset of part sizes matters.

Key Insights

Integer Partitions and Set Partitions: The Core Connection

An integer partition of 5 into at most 4 parts means writing 5 as a sum of positive integers, where the number of summands is at most 4, and order doesn’t matter. For example:

• 5
  
• 4 + 1
  
• 3 + 2
  
• 3 + 1 + 1
  
• 2 + 2 + 1
  
• 2 + 1 + 1 + 1

Each such partition directly corresponds to a valid way of assigning the 5 labeled elements into indistinct bins such that the total number of non-empty bins is ≤ 4, and exactly 4 bins are used with emptiness possibly allowed—however, only partitions with at most 4 parts apply here. Since we’re forming partitions into 4 bins (possibly with empty ones), but requiring “exactly 4” suggests counting configurations where exactly 4 bins are defined—thus only partitions with exactly 4 parts (or fewer, padded with empties) are valid.

But since we’re counting distinct unlabeled partitions using up to 4 parts, the empty bins are implicitly accounted for. For example:

Final Thoughts

• Partition type (5): one bin with all 5 labeled items (space for 3 empty bins)
  
• (4+1): one bin holds 4, one holds 1 (1 empty bin), others empty
  
• (3+2): two bins, one with 3, one with 2 (2 empty bins)
  
• (3+1+1): three bins (2 empty)
  
• (2+2+1): three bins (1 empty)
  
• (2+1+1+1): four bins, all singletons (no empty bin)

These are all possible distinct ways to group 5 labeled objects into up to 4 indistinct groups—each partition shape is counted once.

Why 6 Distinct Partitions Exist

From combinatorics, the number of integer partitions of 5 with at most 4 parts is simple to list:

1. 5
   
2. 4 + 1
   
3. 3 + 2
   
4. 3 + 1 + 1
   
5. 2 + 2 + 1
   
6. 2 + 1 + 1 + 1