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📰 Solution: This is equivalent to partitioning 6 distinct compounds into 3 non-empty, unordered subsets (phases). The number of ways is the Stirling number of the second kind $ S(6, 3) $, multiplied by the number of ways to assign these subsets to 3 distinguishable phases (since phases are distinct, e.g., Phase 1, 2, 3).
📰 First, compute $ S(6, 3) = 90 $. Then multiply by $ 3! = 6 $ to assign the subsets to phases:
📰 $$Question: What is the least common multiple of 15 and 25, representing the cycles of two sedimentary rock deposition patterns in the Grand Canyon?
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